GB0-382 Web-based Practice Exam

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H3CSE-RS-RT Sample Questions (Q119-Q124):

NEW QUESTION # 119
下列对于 Route-polic 的描述中,不正确的是 ______________?

A. 在 Route-polic 的同一个节点中,不同 if-match 子句之间的关系为与
B. 在一个 Route-polic 中,不同节点之间的关系为或
C. 在 Route-polic 的一个节点中,必须至少包含一个 if-match 子句
D. 如果 Route-polic 中定义了一个以上的节点,各节点中至少应该有一个节点的匹配模式是 permit

Answer: C

NEW QUESTION # 120
如图所示 IS-IS 网络中, RTA 和 RTB 配置如下 :

[RTA] isis
[RTA-isis-1] is-level level-1
[RTA-isis-1] network-entit01.1111.1111.1111.00
[RTA-isis-1] interface serial 2/0
[RTA-Serial2/0] isis enable 1
[RTB] isis
[RTB-isis-1] network-entit01.2222.2222.2222.00
[RTB-isis-1] interface serial 1/0
[RTB-Serial1/0] isis enable 1
[RTB-Serial1/0] isis circuit-level level-1
那么 RTA 和 RTB 间

A. 只建立 Level-2 邻接关系
B. 无法建立邻接关系
C. 同时建立 Level-1 和 Level-2 邻接关系
D. 只建立 Level-1 邻接关系

Answer: D

NEW QUESTION # 121
在如图所示的拓扑中, RTA 、 RTB 上分别执行如下配置 :
[RTA] ospf 1
[RTA-ospf-1] area 1
[RTA-ospf-1-area-0.0.0.1] network 10.0.0.0 0.0.0.255
[RTB] ospf 1
[RTB-ospf-1] area 1
[RTB-ospf-1-area-0.0.0.1] network 10.0.0.0 0.0.0.255
[RTB-ospf-1-area-0.0.0.1] area 0
[RTB-ospf-1-area-0.0.0.0] network 20.0.0.0 0.0.0.255
如果需要将区域 2 配置为 TotallStub 区域,则应当在 RTC 和 RTD 上如何配置 ?

A. [RTC] ospf 1 [RTC-ospf-1] area 0 [RTC-ospf-1-area-0.0.0.0] network 20.0.0.0 0.0.0.255 [RTC-ospf-1-area-0.0.0.0] area 2 [RTC-ospf-1-area-0.0.0.2] stub no-summar [RTC-ospf-1-area-0.0.0.2] network 30.0.0.0 0.0.0.255 [RTD] ospf 1 [RTD-ospf-1] area 2 [RTD-ospf-1-area-0.0.0.2] network 30.0.0.0 0.0.0.255 [RTD-ospf-1] area 0 [RTD-ospf-1-area-0.0.0.0] stub
B. [RTC] ospf 1 [RTC-ospf-1] area 0 [RTC-ospf-1-area-0.0.0.0] network 20.0.0.0 0.0.0.255 [RTC-ospf-1-area-0.0.0.0] area 2 [RTC-ospf-1-area-0.0.0.2] stub [RTC-ospf-1-area-0.0.0.2] network 30.0.0.0 0.0.0.255 [RTD] ospf 1 [RTD-ospf-1] area 2 [RTD-ospf-1-area-0.0.0.2] network 30.0.0.0 0.0.0.255 [RTD-ospf-1-area-0.0.0.2] stub no-summar
C. [RTC] ospf 1 [RTC-ospf-1] area 0 [RTC-ospf-1-area-0.0.0.0] network 20.0.0.0 0.0.0.255 [RTC-ospf-1-area-0.0.0.0] area 2 [RTC-ospf-1-area-0.0.0.2] stub [RTC-ospf-1-area-0.0.0.2] network 30.0.0.0 0.0.0.255 [RTD] ospf 1 [RTD-ospf-1] area 2 [RTD-ospf-1-area-0.0.0.2] network 20.0.0.0 0.0.0.255 [RTD-ospf-1-area-0.0.0.2] stub
D. [RTC] ospf 1 [RTC-ospf-1] area 0 [RTC-ospf-1-area-0.0.0.0] network 20.0.0.0 0.0.0.255 [RTC-ospf-1-area-0.0.0.0] area 2 [RTC-ospf-1-area-0.0.0.2] stub no-summar [RTC-ospf-1-area-0.0.0.2] network 30.0.0.0 0.0.0.255 [RTD] ospf 1 [RTD-ospf-1] area 2 [RTD-ospf-1-area-0.0.0.2] network 30.0.0.0 0.0.0.255 [RTD-ospf-1-area-0.0.0.2] stub no-summar

Answer: D

NEW QUESTION # 122
z 关于 OSPF 协议的 NSSA 区域,以下说法不正确的有

A. NSSA 区域中可以有多个 ASBR
B. NSSA 区域中只能存在一个 ABR
C. NSSA 区域中的 ABR 一定将 Tpe7 LSA 转换成 Tpe5 LSA
D. NSSA 区域中一定会注入 Tpe7 LSA

Answer: B,C,D

NEW QUESTION # 123
在如图所示的拓扑中, RTA 、 RTB 、 RTC 上分别执行如下配置 :

[RTA-GigabitEthernet0/0] ip address 192.168.2.1 255.255.255.0
[RTA-GigabitEthernet0/0] ospf network-tpe p2p
[RTA] ospf 1 router-id 1.1.1.1
[RTA-ospf-1] area 1
[RTA-ospf-1-area-0.0.0.1] network 192.168.2.0 0.0.0.255
[RTB-GigabitEthernet0/0] ip address 192.168.2.2 255.255.255.0
[RTB-GigabitEthernet0/0] ospf network-tpe p2p
[RTB-GigabitEthernet0/1] ip address 192.168.3.1 255.255.255.0
[RTB-GigabitEthernet0/1] ospf network-tpe p2p
[RTB] ospf 1 router-id 2.2.2.2
[RTB-ospf-1] area 1
[RTB-ospf-1-area-0.0.0.1] network 192.168.2.0 0.0.0.255
[RTB-ospf-1] area 0
[RTB-ospf-1-area-0.0.0.0] network 192.168.3.0 0.0.0.255
[RTC-GigabitEthernet0/0] ip address 192.168.3.2 255.255.255.0
[RTC-GigabitEthernet0/0] ospf network-tpe p2p
[RTC] ospf 1 router-id 3.3.3.3
[RTC-ospf-1] area 0
[RTC-ospf-1-area-0.0.0.0] network 192.168.3.0 0.0.0.255
那么在 RTB 在 OSPF 区域内产生的 LSA 类型有

A. Tpe2 LSA
B. Tpe4 LSA
C. Tpe15 LSA
D. Tpe3 LSA
E. Tpe1 LSA

Answer: D,E

NEW QUESTION # 124
......

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